14-5400/x^2=0

Solution for 14-5400/x^2=0 equation:

14-5400/x^2=0


Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


14*x^2-5400=0

We add all the numbers together, and all the variables

14x^2-5400=0

a = 14; b = 0; c = -5400;
Δ = b2-4ac
Δ = 02-4·14·(-5400)
Δ = 302400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{302400}=\sqrt{14400*21}=\sqrt{14400}*\sqrt{21}=120\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{21}}{2*14}=\frac{0-120\sqrt{21}}{28}
=-\frac{120\sqrt{21}}{28}
=-\frac{30\sqrt{21}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{21}}{2*14}=\frac{0+120\sqrt{21}}{28}
=\frac{120\sqrt{21}}{28}
=\frac{30\sqrt{21}}{7}
$